Complex.Log 方法

定义

命名空间:
System.Numerics
程序集:
System.Numerics.dll, System.Runtime.Numerics.dll
程序集:
netstandard.dll, System.Runtime.Numerics.dll
程序集:
System.Runtime.Numerics.dll
程序集:
System.Numerics.dll
程序集:
netstandard.dll

返回复数的对数。

重载

名称 说明
Log(Complex)

返回指定复数的自然（base e）对数。
Log(Complex, Double)

返回指定基数中指定复数的对数。

Log(Complex)

Source:
Complex.cs
Source:
Complex.cs
Source:
Complex.cs
Source:
Complex.cs
Source:
Complex.cs

返回指定复数的自然（base e）对数。

public:
 static System::Numerics::Complex Log(System::Numerics::Complex value);
public static System.Numerics.Complex Log(System.Numerics.Complex value);
static member Log : System.Numerics.Complex -> System.Numerics.Complex
Public Shared Function Log (value As Complex) As Complex

参数

value
Complex

复数。

返回

Complex

的自然 （base e） 对 value数。

示例

下面的示例演示了该方法 Log 。 它表明，由于缺少数据类型的 Double 精度，将方法返回 Log 的值传递给 Exp 该方法会返回原始 Complex 值。

using System;
using System.Numerics;

public class Example
{
   public static void Main()
   {
      Complex[] values = { new Complex(1.53, 9.26), 
                           new Complex(2.53, -8.12),
                           new Complex(-2.81, 5.32),
                           new Complex(-1.09, -3.43),
                           new Complex(Double.MinValue/2, Double.MinValue/2) };
      foreach (Complex value in values)
         Console.WriteLine("Exp(Log({0}) = {1}", value, 
                           Complex.Exp(Complex.Log(value)));
   }
}
// The example displays the following output:
//       Exp(Log((1.53, 9.26)) = (1.53, 9.26)
//       Exp(Log((2.53, -8.12)) = (2.53, -8.12)
//       Exp(Log((-2.81, 5.32)) = (-2.81, 5.32)
//       Exp(Log((-1.09, -3.43)) = (-1.09, -3.43)
//       Exp(Log((-8.98846567431158E+307, -8.98846567431158E+307)) = (-8.98846567431161E+307, -8.98846567431161E+307)

open System
open System.Numerics

let values =
    [ Complex(1.53, 9.26)
      Complex(2.53, -8.12)
      Complex(-2.81, 5.32)
      Complex(-1.09, -3.43)
      Complex(Double.MinValue / 2.0, Double.MinValue / 2.0) ]

for value in values do
    printfn $"Exp(Log({value}) = {Complex.Exp(Complex.Log(value))}"
// The example displays the following output:
//       Exp(Log((1.53, 9.26)) = (1.53, 9.26)
//       Exp(Log((2.53, -8.12)) = (2.53, -8.12)
//       Exp(Log((-2.81, 5.32)) = (-2.81, 5.32)
//       Exp(Log((-1.09, -3.43)) = (-1.09, -3.43)
//       Exp(Log((-8.98846567431158E+307, -8.98846567431158E+307)) = (-8.98846567431161E+307, -8.98846567431161E+307)

Imports System.Numerics

Module Example
   Public Sub Main()
      Dim values() As Complex = { New Complex(1.53, 9.26), 
                                  New Complex(2.53, -8.12),
                                  New Complex(-2.81, 5.32),
                                  New Complex(-1.09, -3.43),
                                  New Complex(Double.MinValue/2, Double.MinValue/2) }
      For Each value As Complex In values
         Console.WriteLine("Exp(Log({0}) = {1}", value, 
                           Complex.Exp(Complex.Log(value)))
      Next                                  
   End Sub
End Module
' The example displays the following output:
'      Exp(Log((1.53, 9.26)) = (1.53, 9.26)
'      Exp(Log((2.53, -8.12)) = (2.53, -8.12)
'      Exp(Log((-2.81, 5.32)) = (-2.81, 5.32)
'      Exp(Log((-1.09, -3.43)) = (-1.09, -3.43)
'      Exp(Log((-8.98846567431158E+307, -8.98846567431158E+307)) = (-8.98846567431161E+307, -8.98846567431161E+307)

注解

Log(Complex)复数的方法对应于Math.Log(Double)实数的方法。

另请参阅

适用于

Log(Complex, Double)

Source:
Complex.cs
Source:
Complex.cs
Source:
Complex.cs
Source:
Complex.cs
Source:
Complex.cs

返回指定基数中指定复数的对数。

public:
 static System::Numerics::Complex Log(System::Numerics::Complex value, double baseValue);
public static System.Numerics.Complex Log(System.Numerics.Complex value, double baseValue);
static member Log : System.Numerics.Complex * double -> System.Numerics.Complex
Public Shared Function Log (value As Complex, baseValue As Double) As Complex

参数

value
Complex

复数。

baseValue
Double

对数的基数。

返回

Complex

基数的valuebaseValue对数。

注解

Log(Complex, Double)复数的方法对应于Math.Log(Double, Double)实数的方法。

适用于