Double.IsNegativeInfinity(Double) 方法
定义
重要
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返回一个值,该值指示指定的数字是否计算为负无穷大。
public:
static bool IsNegativeInfinity(double d);
public:
static bool IsNegativeInfinity(double d) = System::Numerics::INumberBase<double>::IsNegativeInfinity;
public static bool IsNegativeInfinity(double d);
static member IsNegativeInfinity : double -> bool
Public Shared Function IsNegativeInfinity (d As Double) As Boolean
参数
- d
- Double
双精度浮点数。
返回
true 如果 d 计算结果为 NegativeInfinity,则为 ;否则为 false。
实现
示例
以下代码示例展示了 IsNegativeInfinity 的用法:
// This will return "true".
Console.WriteLine("IsNegativeInfinity(-5.0 / 0) == {0}.", Double.IsNegativeInfinity(-5.0 / 0) ? "true" : "false");
// This will return "true".
printfn $"IsNegativeInfinity(-5.0 / 0) = {Double.IsNegativeInfinity(-5. / 0.)}."
' This will return "True".
Console.Write("IsNegativeInfinity(-5.0 / 0) = ")
If Double.IsNegativeInfinity(-5 / 0) Then
Console.WriteLine("True.")
Else
Console.WriteLine("False.")
End If
if (d > Double.MaxValue)
Console.WriteLine("Your number is bigger than a double.");
if d > Double.MaxValue then
printfn $"Your number is bigger than a double."
If D > Double.MaxValue Then
Console.WriteLine("Your number is bigger than a double.")
End If
// This will equal Infinity.
Console.WriteLine("10.0 minus NegativeInfinity equals {0}.", (10.0 - Double.NegativeInfinity).ToString());
// This will equal Infinity.
printfn $"10.0 minus NegativeInfinity equals {10.0 - Double.NegativeInfinity}."
' This will equal Infinity.
Console.WriteLine("10.0 minus NegativeInfinity equals " + (10 - Double.NegativeInfinity).ToString() + ".")
注解
浮点操作返回 NegativeInfinity 以发出溢出条件的信号。