Complex.Log Metodo

public:
 static System::Numerics::Complex Log(System::Numerics::Complex value);

public static System.Numerics.Complex Log(System.Numerics.Complex value);

static member Log : System.Numerics.Complex -> System.Numerics.Complex

Public Shared Function Log (value As Complex) As Complex

Parametri

Valori restituiti

Logaritmo naturale (base e) di value.

Esempio

Nell'esempio seguente viene illustrato il Log metodo . Mostra che, con una certa tolleranza per la mancanza di precisione del Double tipo di dati, passando il valore restituito dal Log metodo al Exp metodo restituisce il valore originale Complex .

using System;
using System.Numerics;

public class Example
{
   public static void Main()
   {
      Complex[] values = { new Complex(1.53, 9.26), 
                           new Complex(2.53, -8.12),
                           new Complex(-2.81, 5.32),
                           new Complex(-1.09, -3.43),
                           new Complex(Double.MinValue/2, Double.MinValue/2) };
      foreach (Complex value in values)
         Console.WriteLine("Exp(Log({0}) = {1}", value, 
                           Complex.Exp(Complex.Log(value)));
   }
}
// The example displays the following output:
//       Exp(Log((1.53, 9.26)) = (1.53, 9.26)
//       Exp(Log((2.53, -8.12)) = (2.53, -8.12)
//       Exp(Log((-2.81, 5.32)) = (-2.81, 5.32)
//       Exp(Log((-1.09, -3.43)) = (-1.09, -3.43)
//       Exp(Log((-8.98846567431158E+307, -8.98846567431158E+307)) = (-8.98846567431161E+307, -8.98846567431161E+307)

open System
open System.Numerics

let values =
    [ Complex(1.53, 9.26)
      Complex(2.53, -8.12)
      Complex(-2.81, 5.32)
      Complex(-1.09, -3.43)
      Complex(Double.MinValue / 2.0, Double.MinValue / 2.0) ]

for value in values do
    printfn $"Exp(Log({value}) = {Complex.Exp(Complex.Log(value))}"
// The example displays the following output:
//       Exp(Log((1.53, 9.26)) = (1.53, 9.26)
//       Exp(Log((2.53, -8.12)) = (2.53, -8.12)
//       Exp(Log((-2.81, 5.32)) = (-2.81, 5.32)
//       Exp(Log((-1.09, -3.43)) = (-1.09, -3.43)
//       Exp(Log((-8.98846567431158E+307, -8.98846567431158E+307)) = (-8.98846567431161E+307, -8.98846567431161E+307)

Imports System.Numerics

Module Example
   Public Sub Main()
      Dim values() As Complex = { New Complex(1.53, 9.26), 
                                  New Complex(2.53, -8.12),
                                  New Complex(-2.81, 5.32),
                                  New Complex(-1.09, -3.43),
                                  New Complex(Double.MinValue/2, Double.MinValue/2) }
      For Each value As Complex In values
         Console.WriteLine("Exp(Log({0}) = {1}", value, 
                           Complex.Exp(Complex.Log(value)))
      Next                                  
   End Sub
End Module
' The example displays the following output:
'      Exp(Log((1.53, 9.26)) = (1.53, 9.26)
'      Exp(Log((2.53, -8.12)) = (2.53, -8.12)
'      Exp(Log((-2.81, 5.32)) = (-2.81, 5.32)
'      Exp(Log((-1.09, -3.43)) = (-1.09, -3.43)
'      Exp(Log((-8.98846567431158E+307, -8.98846567431158E+307)) = (-8.98846567431161E+307, -8.98846567431161E+307)

Commenti

Il Log(Complex) metodo per i numeri complessi corrisponde al Math.Log(Double) metodo per i numeri reali.

Vedi anche

• Log(Double)
• Exp(Complex)

public:
 static System::Numerics::Complex Log(System::Numerics::Complex value, double baseValue);

public static System.Numerics.Complex Log(System.Numerics.Complex value, double baseValue);

static member Log : System.Numerics.Complex * double -> System.Numerics.Complex

Public Shared Function Log (value As Complex, baseValue As Double) As Complex

Parametri

Valori restituiti

Logaritmo di value in base baseValue.

Commenti

Il Log(Complex, Double) metodo per i numeri complessi corrisponde al Math.Log(Double, Double) metodo per i numeri reali.