Double.MinValue Feld

public: double MinValue = -1.7976931348623157E+308;

public const double MinValue = -1.7976931348623157E+308;

val mutable MinValue : double

Public Const MinValue As Double  = -1.7976931348623157E+308

Feldwert

Beispiele

Das folgende Codebeispiel veranschaulicht die Verwendung von Double.MinValue:

public class Temperature {
    public static double MinValue {
        get {
            return Double.MinValue;
        }
    }

    public static double MaxValue {
        get {
            return Double.MaxValue;
        }
    }

    // The value holder
    protected double m_value;

    public double Value {
        get {
            return m_value;
        }
        set {
            m_value = value;
        }
    }

    public double Celsius {
        get {
            return (m_value-32.0)/1.8;
        }
        set {
            m_value = 1.8*value+32.0;
        }
    }
}

type Temperature() =
    static member MinValue =
        Double.MinValue

    static member MaxValue =
        Double.MaxValue

    member val Value = 0. with get, set

    member this.Celsius
        with get () =
            (this.Value - 32.) / 1.8
        and set (value) =
            this.Value <- 1.8 * value + 32.

Public Class Temperature

    Public Shared ReadOnly Property MinValue() As Double
        Get
            Return Double.MinValue
        End Get
    End Property

    Public Shared ReadOnly Property MaxValue() As Double
        Get
            Return Double.MaxValue
        End Get
    End Property

    ' The value holder
    Protected m_value As Double

    Public Property Value() As Double
        Get
            Return m_value
        End Get
        Set(ByVal Value As Double)
            m_value = Value
        End Set
    End Property

    Public Property Celsius() As Double
        Get
            Return (m_value - 32) / 1.8
        End Get
        Set(ByVal Value As Double)
            m_value = Value * 1.8 + 32
        End Set
    End Property
End Class

Hinweise

Der Wert dieser Konstante ist negativ 1,7976931348623157E+308.

Das Ergebnis eines Vorgangs, der kleiner als Double.MinValue ist Double.NegativeInfinity. Im folgenden Beispiel ergeben sich Ergebnisse aus Subtraktions- und Multiplikationsvorgängen, Double.NegativeInfinity wenn das Ergebnis kleiner als Double.MinValueist.

using System;

public class Example
{
   public static void Main()
   {
      double result1 = -7.997e307 + -9.985e307;
      Console.WriteLine("{0} (Negative Infinity: {1})",
                        result1, Double.IsNegativeInfinity(result1));

      double result2 = -1.5935e250 * 7.948e110;
      Console.WriteLine("{0} (Negative Infinity: {1})",
                        result2, Double.IsNegativeInfinity(result2));
   }
}
// The example displays the following output:
//    -Infinity (Negative Infinity: True)
//    -Infinity (Negative Infinity: True)

open System

let result1 = -7.997e307 + -9.985e307
printfn $"{result1} (Negative Infinity: {Double.IsNegativeInfinity result1})"

let result2 = -1.5935e250 * 7.948e110
printfn $"{result2} (Negative Infinity: {Double.IsNegativeInfinity result2})"
// The example displays the following output:
//    -Infinity (Negative Infinity: True)
//    -Infinity (Negative Infinity: True)

Module Example
   Public Sub Main()
      Dim result1 As Double = -7.997e307 + -9.985e307
      Console.WriteLine("{0} (Negative Infinity: {1})", 
                        result1, Double.IsNegativeInfinity(result1))
      
      Dim result2 As Double = -1.5935e250 * 7.948e110
      Console.WriteLine("{0} (Negative Infinity: {1})", 
                        result2, Double.IsNegativeInfinity(result2))
   End Sub
End Module
' The example displays the following output:
'    -Infinity (Negative Infinity: True)
'    -Infinity (Negative Infinity: True)