JsonSerializer.SerializeToDocument 方法
定义
重要
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重载
SerializeToDocument(Object, JsonTypeInfo)
将提供的值转换为一个 JsonDocument。
public:
static System::Text::Json::JsonDocument ^ SerializeToDocument(System::Object ^ value, System::Text::Json::Serialization::Metadata::JsonTypeInfo ^ jsonTypeInfo);public static System.Text.Json.JsonDocument SerializeToDocument(object? value, System.Text.Json.Serialization.Metadata.JsonTypeInfo jsonTypeInfo);static member SerializeToDocument : obj * System.Text.Json.Serialization.Metadata.JsonTypeInfo -> System.Text.Json.JsonDocumentPublic Function SerializeToDocument (value As Object, jsonTypeInfo As JsonTypeInfo) As JsonDocument参数
- value
- Object
要转换的值。
- jsonTypeInfo
- JsonTypeInfo
要转换的类型的元数据。
返回
JsonDocument值的表示形式。
例外
jsonTypeInfo 是 null。
value 与类型的 jsonTypeInfo类型不匹配。
适用于
SerializeToDocument(Object, Type, JsonSerializerOptions)
将提供的值转换为一个 JsonDocument。
[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static System.Text.Json.JsonDocument SerializeToDocument(object? value, Type inputType, System.Text.Json.JsonSerializerOptions? options = default);[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static System.Text.Json.JsonDocument SerializeToDocument(object? value, Type inputType, System.Text.Json.JsonSerializerOptions? options = default);public static System.Text.Json.JsonDocument SerializeToDocument(object? value, Type inputType, System.Text.Json.JsonSerializerOptions? options = default);[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member SerializeToDocument : obj * Type * System.Text.Json.JsonSerializerOptions -> System.Text.Json.JsonDocument[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member SerializeToDocument : obj * Type * System.Text.Json.JsonSerializerOptions -> System.Text.Json.JsonDocumentstatic member SerializeToDocument : obj * Type * System.Text.Json.JsonSerializerOptions -> System.Text.Json.JsonDocumentPublic Function SerializeToDocument (value As Object, inputType As Type, Optional options As JsonSerializerOptions = Nothing) As JsonDocument参数
- value
- Object
要转换的值。
- inputType
- Type
要转换的类型 value 。
- options
- JsonSerializerOptions
用于控制转换行为的选项。
返回
JsonDocument值的表示形式。
- 属性
例外
inputType 与 value 不兼容。
inputType 是 null。
无法与inputType序列化成员或其可序列化成员兼容JsonConverter。
适用于
SerializeToDocument(Object, Type, JsonSerializerContext)
将提供的值转换为一个 JsonDocument。
public:
static System::Text::Json::JsonDocument ^ SerializeToDocument(System::Object ^ value, Type ^ inputType, System::Text::Json::Serialization::JsonSerializerContext ^ context);public static System.Text.Json.JsonDocument SerializeToDocument(object? value, Type inputType, System.Text.Json.Serialization.JsonSerializerContext context);static member SerializeToDocument : obj * Type * System.Text.Json.Serialization.JsonSerializerContext -> System.Text.Json.JsonDocumentPublic Function SerializeToDocument (value As Object, inputType As Type, context As JsonSerializerContext) As JsonDocument参数
- value
- Object
要转换的值。
- inputType
- Type
要转换的类型 value 。
- context
- JsonSerializerContext
可序列化类型的元数据提供程序。
返回
JsonDocument值的表示形式。
例外
无法与inputType序列化成员或其可序列化成员兼容JsonConverter。
GetTypeInfo(Type)为要转换的类型提供的context返回null方法。
inputType 或 context 为 null.
适用于
SerializeToDocument<TValue>(TValue, JsonSerializerOptions)
将提供的值转换为一个 JsonDocument。
[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static System.Text.Json.JsonDocument SerializeToDocument<TValue>(TValue value, System.Text.Json.JsonSerializerOptions? options = default);[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static System.Text.Json.JsonDocument SerializeToDocument<TValue>(TValue value, System.Text.Json.JsonSerializerOptions? options = default);public static System.Text.Json.JsonDocument SerializeToDocument<TValue>(TValue value, System.Text.Json.JsonSerializerOptions? options = default);[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member SerializeToDocument : 'Value * System.Text.Json.JsonSerializerOptions -> System.Text.Json.JsonDocument[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member SerializeToDocument : 'Value * System.Text.Json.JsonSerializerOptions -> System.Text.Json.JsonDocumentstatic member SerializeToDocument : 'Value * System.Text.Json.JsonSerializerOptions -> System.Text.Json.JsonDocumentPublic Function SerializeToDocument(Of TValue) (value As TValue, Optional options As JsonSerializerOptions = Nothing) As JsonDocument类型参数
- TValue
要序列化的值的类型。
参数
- value
- TValue
要转换的值。
- options
- JsonSerializerOptions
用于控制转换行为的选项。
返回
JsonDocument JSON 值的表示形式。
- 属性
例外
无法与TValue序列化成员或其可序列化成员兼容JsonConverter。
适用于
SerializeToDocument<TValue>(TValue, JsonTypeInfo<TValue>)
将提供的值转换为一个 JsonDocument。
public:
generic <typename TValue>
static System::Text::Json::JsonDocument ^ SerializeToDocument(TValue value, System::Text::Json::Serialization::Metadata::JsonTypeInfo<TValue> ^ jsonTypeInfo);public static System.Text.Json.JsonDocument SerializeToDocument<TValue>(TValue value, System.Text.Json.Serialization.Metadata.JsonTypeInfo<TValue> jsonTypeInfo);static member SerializeToDocument : 'Value * System.Text.Json.Serialization.Metadata.JsonTypeInfo<'Value> -> System.Text.Json.JsonDocumentPublic Function SerializeToDocument(Of TValue) (value As TValue, jsonTypeInfo As JsonTypeInfo(Of TValue)) As JsonDocument类型参数
- TValue
要序列化的值的类型。
参数
- value
- TValue
要转换的值。
- jsonTypeInfo
- JsonTypeInfo<TValue>
要转换的类型的元数据。
返回
JsonDocument值的表示形式。
例外
无法与TValue序列化成员或其可序列化成员兼容JsonConverter。
jsonTypeInfo 是 null。
