Vector64.ConditionalSelect<T> 方法

定义

按条件从两个向量中按位选择一个值。

public:
generic <typename T>
 static System::Runtime::Intrinsics::Vector64<T> ConditionalSelect(System::Runtime::Intrinsics::Vector64<T> condition, System::Runtime::Intrinsics::Vector64<T> left, System::Runtime::Intrinsics::Vector64<T> right);
public:
generic <typename T>
 where T : value class static System::Runtime::Intrinsics::Vector64<T> ConditionalSelect(System::Runtime::Intrinsics::Vector64<T> condition, System::Runtime::Intrinsics::Vector64<T> left, System::Runtime::Intrinsics::Vector64<T> right);
public static System.Runtime.Intrinsics.Vector64<T> ConditionalSelect<T>(System.Runtime.Intrinsics.Vector64<T> condition, System.Runtime.Intrinsics.Vector64<T> left, System.Runtime.Intrinsics.Vector64<T> right);
public static System.Runtime.Intrinsics.Vector64<T> ConditionalSelect<T>(System.Runtime.Intrinsics.Vector64<T> condition, System.Runtime.Intrinsics.Vector64<T> left, System.Runtime.Intrinsics.Vector64<T> right) where T : struct;
static member ConditionalSelect : System.Runtime.Intrinsics.Vector64<'T> * System.Runtime.Intrinsics.Vector64<'T> * System.Runtime.Intrinsics.Vector64<'T> -> System.Runtime.Intrinsics.Vector64<'T>
static member ConditionalSelect : System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> * System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> * System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> -> System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> (requires 'T : struct)
Public Function ConditionalSelect(Of T) (condition As Vector64(Of T), left As Vector64(Of T), right As Vector64(Of T)) As Vector64(Of T)
Public Function ConditionalSelect(Of T As Structure) (condition As Vector64(Of T), left As Vector64(Of T), right As Vector64(Of T)) As Vector64(Of T)

类型参数

T

向量中的元素的类型。

参数

condition
Vector64<T>

用于从中或从 left 中选择 right值的掩码。

left
Vector64<T>

当相应位为 condition 1 时选择的向量。

right
Vector64<T>

当相应位为 condition 零时选择的向量。

返回

一个矢量,其位来自 leftright 基于其 condition值 。

例外

不支持 /> 的类型)。

注解

返回的向量等效于condition?left:right每位。

适用于