Vector64.ConditionalSelect<T> 方法
定义
重要
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按条件从两个向量中按位选择一个值。
public:
generic <typename T>
static System::Runtime::Intrinsics::Vector64<T> ConditionalSelect(System::Runtime::Intrinsics::Vector64<T> condition, System::Runtime::Intrinsics::Vector64<T> left, System::Runtime::Intrinsics::Vector64<T> right);
public:
generic <typename T>
where T : value class static System::Runtime::Intrinsics::Vector64<T> ConditionalSelect(System::Runtime::Intrinsics::Vector64<T> condition, System::Runtime::Intrinsics::Vector64<T> left, System::Runtime::Intrinsics::Vector64<T> right);
public static System.Runtime.Intrinsics.Vector64<T> ConditionalSelect<T>(System.Runtime.Intrinsics.Vector64<T> condition, System.Runtime.Intrinsics.Vector64<T> left, System.Runtime.Intrinsics.Vector64<T> right);
public static System.Runtime.Intrinsics.Vector64<T> ConditionalSelect<T>(System.Runtime.Intrinsics.Vector64<T> condition, System.Runtime.Intrinsics.Vector64<T> left, System.Runtime.Intrinsics.Vector64<T> right) where T : struct;
static member ConditionalSelect : System.Runtime.Intrinsics.Vector64<'T> * System.Runtime.Intrinsics.Vector64<'T> * System.Runtime.Intrinsics.Vector64<'T> -> System.Runtime.Intrinsics.Vector64<'T>
static member ConditionalSelect : System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> * System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> * System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> -> System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> (requires 'T : struct)
Public Function ConditionalSelect(Of T) (condition As Vector64(Of T), left As Vector64(Of T), right As Vector64(Of T)) As Vector64(Of T)
Public Function ConditionalSelect(Of T As Structure) (condition As Vector64(Of T), left As Vector64(Of T), right As Vector64(Of T)) As Vector64(Of T)
类型参数
- T
向量中的元素的类型。
参数
- condition
- Vector64<T>
用于从中或从 left 中选择 right值的掩码。
- left
- Vector64<T>
当相应位为 condition 1 时选择的向量。
- right
- Vector64<T>
当相应位为 condition 零时选择的向量。
返回
一个矢量,其位来自 left 或 right 基于其 condition值 。
例外
不支持
注解
返回的向量等效于condition?left:right每位。