Byte.IModulusOperators<Byte,Byte,Byte>.Modulus(Byte, Byte) 操作员

定义

命名空间:
System
程序集:
netstandard.dll, System.Runtime.dll
Source:
Byte.cs
Source:
Byte.cs
Source:
Byte.cs
Source:
Byte.cs
Source:
Byte.cs

将两个值相除以计算其模数或余数。

 static System::Byte System.Numerics.IModulusOperators<System.Byte,System.Byte,System.Byte>.operator %(System::Byte left, System::Byte right) = System::Numerics::IModulusOperators<System::Byte, System::Byte, System::Byte>::op_Modulus;
static byte IModulusOperators<byte,byte,byte>.operator %(byte left, byte right);
static member ( % ) : byte * byte -> byte
 Shared Operator Mod (left As Byte, right As Byte) As Byte Implements IModulusOperators(Of Byte, Byte, Byte).op_Modulus

参数

left
Byte

除法的值 right 。

right
Byte

除 left数的值。

返回

Byte

除left以的模数或余数right。

实现

Modulus(TSelf, TOther)

适用于