XmlIncludeAttribute.Type 속성

public:
 property Type ^ Type { Type ^ get(); void set(Type ^ value); };

public Type Type { get; set; }

public Type? Type { get; set; }

member this.Type : Type with get, set

Public Property Type As Type

속성 값

Type 포함할 개체의 개체입니다.

예제

다음 예제에서는 개체 배열 Group 을 반환하는 이름이 지정된 필드를 포함하는 명명 EmployeesEmployee 된 클래스를 정의합니다. 이 예제에서는 Manager 클래스에서 클래스를 Employee 파생하고 클래스에 XmlIncludeAttributeEmployee 적용합니다. 이 예제에서는 개체를 Group 만들 때 배열에 개체를 ManagerEmployee 삽입합니다. 마지막으로 개체를 serialize하는 예제입니다 Group .

using System;
using System.IO;
using System.Xml.Serialization;

public class Group
{
   public Employee[] Employees;
}

// Instruct the XmlSerializer to accept Manager types as well.
[XmlInclude(typeof(Manager))]
public class Employee
{
   public string Name;
}

public class Manager:Employee
{
   public int Level;
}

public class Run
{
   public static void Main()
   {
      Run test = new Run();
      test.SerializeObject("IncludeExample.xml");
      test.DeserializeObject("IncludeExample.xml");
   }

   public void SerializeObject(string filename)
   {
      XmlSerializer s = new XmlSerializer(typeof(Group));
      TextWriter writer = new StreamWriter(filename);
      Group group = new Group();

      Manager manager = new Manager();
      Employee emp1 = new Employee();
      Employee emp2 = new Employee();

      manager.Name = "Zeus";
      manager.Level = 2;

      emp1.Name = "Ares";

      emp2.Name = "Artemis";

      Employee [] emps = new Employee[3]{manager, emp1, emp2};
      group.Employees = emps;

      s.Serialize(writer, group);
      writer.Close();
   }

   public void DeserializeObject(string filename)
   {
      FileStream fs = new FileStream(filename, FileMode.Open);
      XmlSerializer x = new XmlSerializer(typeof(Group));
      Group g = (Group) x.Deserialize(fs);
      Console.Write("Members:");

      foreach(Employee e in g.Employees)
      {
         Console.WriteLine("\t" + e.Name);
      }
   }
}

Imports System.IO
Imports System.Xml.Serialization

Public Class Group
    Public Employees() As Employee
End Class

' Instruct the XmlSerializer to accept Manager types as well.
<XmlInclude(GetType(Manager))> _
Public Class Employee
    Public Name As String
End Class

Public Class Manager
    Inherits Employee
    Public Level As Integer
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("IncludeExample.xml")
        test.DeserializeObject("IncludeExample.xml")
    End Sub    
    
    
    Public Sub SerializeObject(ByVal filename As String)
        Dim s As New XmlSerializer(GetType(Group))
        Dim writer As New StreamWriter(filename)
        Dim group As New Group()
        
        Dim manager As New Manager()
        Dim emp1 As New Employee()
        Dim emp2 As New Employee()
        
        manager.Name = "Zeus"
        manager.Level = 2
        
        emp1.Name = "Ares"
        
        emp2.Name = "Artemis"
        
        Dim emps() As Employee = {manager, emp1, emp2}
        group.Employees = emps
        
        s.Serialize(writer, group)
        writer.Close()
    End Sub    
    
    Public Sub DeserializeObject(ByVal filename As String)
        Dim fs As New FileStream(filename, FileMode.Open)
        Dim x As New XmlSerializer(GetType(Group))
        Dim g As Group = CType(x.Deserialize(fs), Group)
        Console.Write("Members:")
        
        Dim e As Employee
        For Each e In  g.Employees
            Console.WriteLine(ControlChars.Tab + e.Name)
        Next e
    End Sub
End Class