BitArray.And(BitArray) Méthode

public:
 System::Collections::BitArray ^ And(System::Collections::BitArray ^ value);

public System.Collections.BitArray And(System.Collections.BitArray value);

member this.And : System.Collections.BitArray -> System.Collections.BitArray

Public Function And (value As BitArray) As BitArray

Paramètres

Retours

Tableau contenant le résultat de l’opération AND au niveau du bit, qui est une référence à l’objet actuel BitArray .

Exceptions

Exemples

L’exemple de code suivant montre comment effectuer l’opération AND au niveau du bit entre deux BitArray objets.

using System;
using System.Collections;
public class SamplesBitArray  {

   public static void Main()  {

      // Creates and initializes two BitArrays of the same size.
      BitArray myBA1 = new BitArray( 4 );
      BitArray myBA2 = new BitArray( 4 );
      myBA1[0] = myBA1[1] = false;
      myBA1[2] = myBA1[3] = true;
      myBA2[0] = myBA2[2] = false;
      myBA2[1] = myBA2[3] = true;

      // Performs a bitwise AND operation between BitArray instances of the same size.
      Console.WriteLine( "Initial values" );
      Console.Write( "myBA1:" );
      PrintValues( myBA1, 8 );
      Console.Write( "myBA2:" );
      PrintValues( myBA2, 8 );
      Console.WriteLine();

      Console.WriteLine( "Result" );
      Console.Write( "AND:" );
      PrintValues( myBA1.And( myBA2 ), 8 );
      Console.WriteLine();

      Console.WriteLine( "After AND" );
      Console.Write( "myBA1:" );
      PrintValues( myBA1, 8 );
      Console.Write( "myBA2:" );
      PrintValues( myBA2, 8 );
      Console.WriteLine();

      // Performing AND between BitArray instances of different sizes returns an exception.
      try  {
         BitArray myBA3 = new BitArray( 8 );
         myBA3[0] = myBA3[1] = myBA3[2] = myBA3[3] = false;
         myBA3[4] = myBA3[5] = myBA3[6] = myBA3[7] = true;
         myBA1.And( myBA3 );
      } catch ( Exception myException )  {
         Console.WriteLine("Exception: " + myException.ToString());
      }
   }

   public static void PrintValues( IEnumerable myList, int myWidth )  {
      int i = myWidth;
      foreach ( Object obj in myList ) {
         if ( i <= 0 )  {
            i = myWidth;
            Console.WriteLine();
         }
         i--;
         Console.Write( "{0,8}", obj );
      }
      Console.WriteLine();
   }
}


/*
This code produces the following output.

Initial values
myBA1:   False   False    True    True
myBA2:   False    True   False    True

Result
AND:   False   False   False    True

After AND
myBA1:   False   False   False    True
myBA2:   False    True   False    True

Exception: System.ArgumentException: Array lengths must be the same.
   at System.Collections.BitArray.And(BitArray value)
   at SamplesBitArray.Main()
*/

Imports System.Collections

Public Class SamplesBitArray    
    
    Public Shared Sub Main()
        
        ' Creates and initializes two BitArrays of the same size.
        Dim myBA1 As New BitArray(4)
        Dim myBA2 As New BitArray(4)
        myBA1(1) = False
        myBA1(0) = False
        myBA1(3) = True
        myBA1(2) = True
        myBA2(2) = False
        myBA2(0) = False
        myBA2(3) = True
        myBA2(1) = True
        
        ' Performs a bitwise AND operation between BitArray instances of the same size.
        Console.WriteLine("Initial values")
        Console.Write("myBA1:")
        PrintValues(myBA1, 8)
        Console.Write("myBA2:")
        PrintValues(myBA2, 8)
        Console.WriteLine()
        
        Console.WriteLine("Result")
        Console.Write("AND:")
        PrintValues(myBA1.And(myBA2), 8)
        Console.WriteLine()
        
        Console.WriteLine("After AND")
        Console.Write("myBA1:")
        PrintValues(myBA1, 8)
        Console.Write("myBA2:")
        PrintValues(myBA2, 8)
        Console.WriteLine()
        
        ' Performing AND between BitArray instances of different sizes returns an exception.
        Try
            Dim myBA3 As New BitArray(8)
            myBA3(0) = False
            myBA3(1) = False
            myBA3(2) = False
            myBA3(3) = False
            myBA3(4) = True
            myBA3(5) = True
            myBA3(6) = True
            myBA3(7) = True
            myBA1.And(myBA3)
        Catch myException As Exception
            Console.WriteLine("Exception: " + myException.ToString())
        End Try
    End Sub

    Public Shared Sub PrintValues(myList As IEnumerable, myWidth As Integer)
        Dim i As Integer = myWidth
        Dim obj As [Object]
        For Each obj In  myList
            If i <= 0 Then
                i = myWidth
                Console.WriteLine()
            End If
            i -= 1
            Console.Write("{0,8}", obj)
        Next obj
        Console.WriteLine()
    End Sub

End Class


' This code produces the following output.
' 
' Initial values
' myBA1:   False   False    True    True
' myBA2:   False    True   False    True
'
' Result
' AND:   False   False   False    True
'
' After AND
' myBA1:   False   False   False    True
' myBA2:   False    True   False    True
'
' Exception: System.ArgumentException: Array lengths must be the same.
'    at System.Collections.BitArray.And(BitArray value)
'    at SamplesBitArray.Main()

Remarques

L’opération AND au niveau du bit retourne true si les deux opérandes sont true, et retourne false si un ou les deux opérandes sont false.

Cette méthode est une O(n) opération, où n est Count.